ParserFunctions should not be subst'ed, only their output
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	• bzimport
	Nov 29 2006, 8:50 PM

Description

Author: circeus

Description:
I can't tell whether this is or not a duplicate of bug 7051. It might be related
to now fixed bug 3298 (Subst'ing ignore includeonly/noinclude).

When you subst a template with ParserFunctions, the ParserFunctions syntax ends
up in the article, whereas you would only want the output. This is especially
troublesome with templates like [[:en:Category:Conversion templates]], which
can't be subst'ed.

Version: unspecified
Severity: normal
OS: Windows XP
Platform: PC

Details

Reference: bz8081

Event Timeline

• bzimport raised the priority of this task from to Medium.Nov 21 2014, 9:32 PM

• bzimport added a project: MediaWiki-extensions-General.

• bzimport set Reference to bz8081.

• bzimport added a subscriber: Unknown Object (MLST).

• bzimport created this task.Nov 29 2006, 8:50 PM

robchur wrote:

When you substitute a template with text in it, that text ends up in the page.
If you substitute a template containing a template, what happens?

This is a duplicate of that larger behaviour.

ayg wrote:

*** This bug has been marked as a duplicate of 2777 ***

ParserFunctions should not be subst'ed, only their outputClosed, ResolvedPublicActions

Description

Details

Event Timeline

ParserFunctions should not be subst'ed, only their output
Closed, ResolvedPublic
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